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TL;DR

Ito's Lemma: The chain rule for stochastic calculus: df = f'dX + (1/2)f''(dX)^2 — the extra term changes everything. This concept is essential for quantitative trading interviews and is frequently tested at top firms.

By Valenke Exam Prep Team·Last updated 2026-06-01
Stochastic Processes

Ito's Lemma

The chain rule for stochastic calculus: df = f'dX + (1/2)f''(dX)^2 — the extra term changes everything.

Ito's lemma is the chain rule of stochastic calculus. If XtX_t follows dXt=μ dt+σ dWtdX_t = \mu \, dt + \sigma \, dW_t and f(t,x)f(t, x) is a smooth function, then: df=∂f∂tdt+∂f∂xdXt+12∂2f∂x2(dXt)2df = \frac{\partial f}{\partial t} dt + \frac{\partial f}{\partial x} dX_t + \frac{1}{2} \frac{\partial^2 f}{\partial x^2} (dX_t)^2 Using (dWt)2=dt(dW_t)^2 = dt, dWt⋅dt=0dW_t \cdot dt = 0, (dt)2=0(dt)^2 = 0: df=(∂f∂t+μ∂f∂x+σ22∂2f∂x2)dt+σ∂f∂xdWtdf = \left(\frac{\partial f}{\partial t} + \mu \frac{\partial f}{\partial x} + \frac{\sigma^2}{2} \frac{\partial^2 f}{\partial x^2}\right) dt + \sigma \frac{\partial f}{\partial x} dW_t Intuition: In ordinary calculus, the Taylor expansion's second-order term 12f′′(dx)2\frac{1}{2}f''(dx)^2 vanishes because (dx)2(dx)^2 is infinitesimally small compared to dxdx. But Brownian motion is "rougher" than smooth paths — (dW)2(dW)^2 is of order dtdt, not (dt)2(dt)^2. So the second-order term survives! This is the fundamental surprise of stochastic calculus. The classic application — deriving GBM: Let dS=μS dt+σS dWdS = \mu S \, dt + \sigma S \, dW and apply Ito's lemma to f(S)=ln⁡Sf(S) = \ln S: - f′=1/Sf' = 1/S, f′′=−1/S2f'' = -1/S^2 - d(ln⁡S)=1S(μS dt+σS dW)+12(−1/S2)(σS)2dtd(\ln S) = \frac{1}{S}(\mu S \, dt + \sigma S \, dW) + \frac{1}{2}(-1/S^2)(\sigma S)^2 dt - d(ln⁡S)=(μ−σ2/2)dt+σ dWd(\ln S) = (\mu - \sigma^22\frac{2}{2}) dt + \sigma \, dW The −σ2/2-\sigma^22\frac{2}{2} correction appears naturally — it's not an ad hoc adjustment, it's Ito's lemma at work. Concrete example: Let f(Wt)=Wt2f(W_t) = W_t^2. By Ito's lemma (f′=2Wtf'= 2W_t, f′′=2f''=2): d(Wt2)=2Wt dWt+12(2)(dWt)2=2Wt dWt+dtd(W_t^2) = 2W_t \, dW_t + \frac{1}{2}(2)(dW_t)^2 = 2W_t \, dW_t + dt So Wt2=2∫0tWs dWs+tW_t^2 = 2\int_0^t W_s \, dW_s + t, which gives E[Wt2]=tE[W_t^2] = t. The extra dtdt term is pure Ito. When to use: Any time you need to find the dynamics of a function of a stochastic process. Deriving the Black-Scholes PDE. Computing expectations of transformed processes. This is the workhorse of quantitative finance.

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