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TL;DR

Taylor Series Approximation: Approximate any smooth function locally as a polynomial: f(x) ≈ f(a) + f'(a)(x-a) + ... This concept is essential for quantitative trading interviews and is frequently tested at top firms.

By Valenke Exam Prep Team·Last updated 2026-06-01
Analysis

Taylor Series Approximation

Approximate any smooth function locally as a polynomial: f(x) ≈ f(a) + f'(a)(x-a) + ...

A Taylor series expands a smooth function ff around a point aa as an infinite polynomial: f(x)=n=0f(n)(a)n!(xa)n=f(a)+f(a)(xa)+f(a)2!(xa)2+f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots When a=0a = 0, this is called a Maclaurin series. Intuition: You're building a polynomial that matches ff at aa in value, slope, curvature, and every higher derivative. Each term corrects the next order of approximation. For points close to aa, even a few terms give excellent accuracy. Essential expansions you should know: - ex=1+x+x22!+x33!+e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots - ln(1+x)=xx22+x33\ln(1+x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \cdots for x<1|x| < 1 - 11x=1+x+x2+x3+\frac{1}{1-x} = 1 + x + x^2 + x^3 + \cdots for x<1|x| < 1 - (1+x)α=1+αx+α(α1)2!x2+(1+x)^\alpha = 1 + \alpha x + \frac{\alpha(\alpha-1)}{2!}x^2 + \cdots (binomial series) Concrete example: Approximate e0.1e^{0.1}. Using two terms: e0.11+0.1+0.01/2=1.105e^{0.1} \approx 1 + 0.1 + 0.012\frac{01}{2} = 1.105. Exact value: 1.10517...1.10517... — error of 0.02%. When to use: Approximating complicated expressions (especially in finance: ln(1+r)r\ln(1+r) \approx r for small rr). Deriving results in probability (moment generating functions). Simplifying integrals. The backbone of perturbation methods. This is a fundamental technique — arguably the single most useful technique in applied mathematics.

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