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TL;DR

Ito Isometry: The variance of a stochastic integral equals the integral of the squared integrand. This concept is essential for quantitative trading interviews and is frequently tested at top firms.

By Valenke Exam Prep Team·Last updated 2026-06-01
Stochastic Processes

Ito Isometry

The variance of a stochastic integral equals the integral of the squared integrand.

The Ito isometry is the fundamental rule for computing the variance of stochastic integrals. If f(t)f(t) is a (sufficiently nice) deterministic function, then: E ⁣[(0Tf(t)dWt) ⁣2]=0Tf(t)2dtE\!\left[\left(\int_0^T f(t)\, dW_t\right)^{\!2}\right] = \int_0^T f(t)^2\, dt More generally, for adapted processes f(t,ω)f(t, \omega): E ⁣[(0Tf(t)dWt) ⁣2]=E ⁣[0Tf(t)2dt]E\!\left[\left(\int_0^T f(t)\, dW_t\right)^{\!2}\right] = E\!\left[\int_0^T f(t)^2\, dt\right] Intuition: Ordinary integrals add up signed areas, so squaring an integral involves cross terms. But Brownian increments dWtdW_t at different times are independent, so all cross terms vanish in expectation. The only surviving terms are the squared ones — just like how Var(Xi)=Var(Xi)\text{Var}(\sum X_i) = \sum \text{Var}(X_i) when the XiX_i are independent. Concrete example: Compute Var ⁣(0TWtdWt)\text{Var}\!\left(\int_0^T W_t\, dW_t\right). Since 0TWtdWt\int_0^T W_t\, dW_t is a martingale with zero mean, its variance equals: E ⁣[0TWt2dt]=0TE[Wt2]dt=0Ttdt=T22E\!\left[\int_0^T W_t^2\, dt\right] = \int_0^T E[W_t^2]\, dt = \int_0^T t\, dt = \frac{T^2}{2} When to use: Any time you need the variance or second moment of a stochastic integral — pricing, hedging error analysis, or verifying that a process is a true martingale (finite second moment). The isometry also underpins the construction of the Ito integral itself.

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