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TL;DR

Poisson Process: Events arriving randomly in time with constant rate — the backbone of continuous-time probability. This concept is essential for quantitative trading interviews and is frequently tested at top firms.

By Valenke Exam Prep Team·Last updated 2026-06-01
Stochastic Processes

Poisson Process

Events arriving randomly in time with constant rate — the backbone of continuous-time probability.

A Poisson process with rate λ\lambda is a counting process N(t)N(t) where events arrive randomly in continuous time with the following properties: 1. N(0)=0N(0) = 0 2. Independent increments: counts in non-overlapping intervals are independent 3. N(t+s)N(t)Poisson(λs)N(t+s) - N(t) \sim \text{Poisson}(\lambda s) for any t,s0t, s \ge 0 The key connections: - Number of events in time tt: N(t)Poisson(λt)N(t) \sim \text{Poisson}(\lambda t), so E[N(t)]=λtE[N(t)] = \lambda t and Var(N(t))=λt\text{Var}(N(t)) = \lambda t - Time between events: Exp(λ)\text{Exp}(\lambda), with E[T]=1/λE[T] = 1/\lambda - Time to kk-th event: Gamma(k,λ)\text{Gamma}(k, \lambda) Concrete example: Customers arrive at a shop at rate 5 per hour. What is the probability of seeing exactly 3 customers in 30 minutes? The rate for half an hour is λt=5×0.5=2.5\lambda t = 5 \times 0.5 = 2.5: P(N=3)=e2.52.533!=e2.515.62560.214P(N = 3) = \frac{e^{-2.5} \cdot 2.5^3}{3!} = \frac{e^{-2.5} \cdot 15.625}{6} \approx 0.214 Superposition: Merging two independent Poisson processes with rates λ1,λ2\lambda_1, \lambda_2 gives a Poisson process with rate λ1+λ2\lambda_1 + \lambda_2. Thinning: Randomly keeping each event with probability pp gives a Poisson process with rate pλp\lambda. When to use: Modeling arrivals, defaults, trades, or any events occurring "randomly" at a constant average rate. The memoryless property of exponential interarrival times makes it the natural starting point for continuous-time models in finance and queueing.

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