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TL;DR

Order Statistics: The k-th smallest value from a sample — connects sorting to probability. This concept is essential for quantitative trading interviews and is frequently tested at top firms.

By Valenke Exam Prep Team·Last updated 2026-06-01
Probability

Order Statistics

The k-th smallest value from a sample — connects sorting to probability.

Given nn random variables X1,,XnX_1, \ldots, X_n, the order statistics are the sorted values X(1)X(2)X(n)X_{(1)} \le X_{(2)} \le \cdots \le X_{(n)}. So X(1)=minX_{(1)} = \min, X(n)=maxX_{(n)} = \max, and X(k)X_{(k)} is the kk-th smallest. The fundamental CDF: For nn i.i.d. draws from CDF FF: P(X(k)x)=j=kn(nj)[F(x)]j[1F(x)]njP(X_{(k)} \le x) = \sum_{j=k}^{n} \binom{n}{j} [F(x)]^j [1 - F(x)]^{n-j} Intuition: X(k)xX_{(k)} \le x means at least kk of the nn values fall at or below xx, which is a binomial sum with success probability F(x)F(x). Concrete example: Two players draw independently from Uniform[0,1][0,1]. What is E[max(X1,X2)]E[\max(X_1, X_2)]? The CDF of the max is P(X(2)x)=x2P(X_{(2)} \le x) = x^2, so the PDF is 2x2x, giving: E[X(2)]=01x2xdx=23E[X_{(2)}] = \int_0^1 x \cdot 2x\, dx = \frac{2}{3} More generally, for nn Uniform[0,1][0,1] draws: E[X(k)]=kn+1E[X_{(k)}] = \frac{k}{n+1}. The Beta connection: For Uniform[0,1][0,1] samples, X(k)Beta(k,nk+1)X_{(k)} \sim \text{Beta}(k, n-k+1). This is extremely useful in auction theory, where bidders draw values from a distribution and the highest or second-highest order statistic determines the outcome. When to use: Auction theory (revenue = function of order statistics), extreme value problems, best-of-nn scenarios, and any problem involving "the kk-th largest draw."

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