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TL;DR

Cramer-Rao Lower Bound: No unbiased estimator can have variance below 1/I(theta) — the precision floor. This concept is essential for quantitative trading interviews and is frequently tested at top firms.

By Valenke Exam Prep Team·Last updated 2026-06-01
Probability

Cramer-Rao Lower Bound

No unbiased estimator can have variance below 1/I(theta) — the precision floor.

Prerequisites

The Cramer-Rao lower bound (CRLB) sets a fundamental limit on how precisely you can estimate a parameter. For any unbiased estimator θ^\hat{\theta} of θ\theta: Var(θ^)1I(θ)\text{Var}(\hat{\theta}) \geq \frac{1}{I(\theta)} where I(θ)I(\theta) is the Fisher information. For nn i.i.d. observations: Var(θ^)1nI(θ)\text{Var}(\hat{\theta}) \geq \frac{1}{n \cdot I(\theta)}. Intuition: Fisher information measures how "informative" data is about θ\theta. The CRLB says: the more informative your data, the lower your estimation error can be — but there's a hard floor. No amount of cleverness in your estimator can beat this bound. An estimator that achieves equality is called efficient. Proof sketch: Apply Cauchy-Schwarz to Cov(θ^,score)\text{Cov}(\hat{\theta}, \text{score}). Since the score has mean 0 and variance I(θ)I(\theta), and Cov(θ^,score)=1\text{Cov}(\hat{\theta}, \text{score}) = 1 for unbiased estimators, we get 1Var(θ^)I(θ)1 \leq \sqrt{\text{Var}(\hat{\theta}) \cdot I(\theta)}. Concrete example: Estimating the mean μ\mu of a normal distribution N(μ,σ2)N(\mu, \sigma^2) from nn samples. Fisher information per observation: I(μ)=1/σ2I(\mu) = 1/\sigma^2. CRLB: Var(μ^)σ2/n\text{Var}(\hat{\mu}) \geq \sigma^2/n. The sample mean Xˉ\bar{X} achieves exactly this — it's efficient. When to use: Evaluating whether your estimator is any good (compare its variance to the CRLB). Proving that a particular estimator is optimal. In adaptive testing, the standard error from EAP estimation is bounded by 1/I(θ)1/\sqrt{I(\theta)} — the CRLB tells you when you've extracted enough information to stop.

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