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TL;DR

Bayes' Theorem: Flip conditional probabilities: P(A|B) = P(B|A) * P(A) / P(B). This concept is essential for quantitative trading interviews and is frequently tested at top firms.

By Valenke Exam Prep Team·Last updated 2026-06-01
Probability

Bayes' Theorem

Flip conditional probabilities: P(A|B) = P(B|A) * P(A) / P(B).

Bayes' theorem lets you reverse the direction of a conditional probability: P(AB)=P(BA)P(A)P(B)P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)} Or in the full "partition" form with hypotheses H1,,HnH_1, \ldots, H_n: P(HiE)=P(EHi)P(Hi)j=1nP(EHj)P(Hj)P(H_i|E) = \frac{P(E|H_i) \cdot P(H_i)}{\sum_{j=1}^{n} P(E|H_j) \cdot P(H_j)} Intuition: You observe evidence EE. You want to know which hypothesis caused it. Bayes says: start with your prior belief P(Hi)P(H_i), multiply by how likely the evidence is under that hypothesis P(EHi)P(E|H_i), then normalize so everything sums to 1. Evidence that is more likely under hypothesis HiH_i pushes you toward believing HiH_i. Concrete example: A medical test is 99% sensitive (catches 99% of sick people) and 95% specific (5% false positive rate). The disease prevalence is 1%. You test positive. What's the probability you're actually sick? P(sick+)=0.99×0.010.99×0.01+0.05×0.99=0.00990.0099+0.049516.7%P(\text{sick}|+) = \frac{0.99 \times 0.01}{0.99 \times 0.01 + 0.05 \times 0.99} = \frac{0.0099}{0.0099 + 0.0495} \approx 16.7\% Despite a "99% accurate" test, the low base rate means most positives are false alarms! 1000 people tested 10 sick 990 healthy ~10 TP ~50 FP 940 TN P(sick|+) = 1060\frac{10}{60} ≈ 17% When to use: Any problem that gives you P(BA)P(B|A) but asks for P(AB)P(A|B). Medical diagnostics, spam filtering, updating beliefs with new evidence, and nearly all Bayesian statistics. This is a fundamental technique — arguably the most fundamental result in probability. It underpins Bayesian inference, machine learning, and decision-making under uncertainty.

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